What is the hybrid orbital configuration of a carbon atom in an ethylene molecule (C2H4) containing a double bond?
Answer and explanation
Correct answer: D. sp^2 hybridization with trigonal planar geometry
- Step 1: Each carbon in ethylene forms 3 sigma bonds and 1 pi bond, requiring 3 hybrid orbitals (sp^2) arranged in a planar 120 deg triangle. Answer: sp^2 hybridization with trigonal planar geometry. Why not the others: sp^3 is for single bonds (ethane); sp is for triple bonds (acetylene).
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