What is the vertex and maximum value of the quadratic function f(x) = -2x^2 + 8x - 3?
Answer and explanation
Correct answer: B. vertex at (2, 5) with maximum value 5
- Step 1: Vertex x-coordinate h = -b/(2a) = -8/(2 -2) = 2. Step 2. Evaluate k = f(2) = -2(4) + 8(2) - 3 = -8 + 16 - 3 = 5. Step 3. Since a = -2 < 0, the parabola opens downward with a maximum at (2, 5). Answer: vertex at (2, 5) with maximum value 5. Why not the others:* x = 2, not -2.
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