From an external point P, a tangent PT of length 6 cm and a secant PAB are drawn such that PA = 4 cm. What is the length of chord AB?
Answer and explanation
Correct answer: A. 5 cm
- Step 1: Tangent-Secant Theorem: PT^2 = PA PB. Step 2. 6^2 = 4 PB => 36 = 4 PB => PB = 9 cm. Step 3. Chord AB = PB - PA = 9 - 4 = 5 cm. Answer: 5 cm. Why not the others:* 9 cm is PB, not chord AB.
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