A snail at the bottom of a 10-meter deep well climbs up 3 meters each day, but slips down 2 meters each night. On which day will the snail reach the top of the well?
Answer and explanation
Correct answer: C. Day 8
- Step 1: Net gain per 24-hour cycle is per day.
- Step 2: At the end of Day 7, the snail reaches .
- Step 3: On Day 8, during the daytime climb, the snail advances 3 meters: .
- Step 4: The snail reaches the top on Day 8 and does not slip down.
Answer
Day 8.
Why not the others: 'Day 10' calculates , forgetting that the snail exits during the daytime of Day 8; 'Day 9' miscounts the final jump; 'Day 7' reaches only 7 meters.
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