An ideal gas initially occupying a volume of 2.0 L at 300 K and 1.0 atm is heated isobarically (at constant pressure) until its temperature reaches 450 K. What is its new volume?
Answer and explanation
Correct answer: C. 3.0 L
- Step 1: State Charles's Law for isobaric processes: V1 / T1 = V2 / T2 (with temperature in Kelvin).
- Step 2: Substitute known values: 2.0 / 300 = V2 / 450.
- Step 3: Solve for V2: V2 = 2.0 (450 / 300) = 2.0 1.5 = 3.0 L.
Answer
3.0 L.
Why not the others: '2.5 L' calculates a 25% increase instead of 50%; '4.0 L' doubles volume erroneously; '1.5 L' inverts the temperature ratio.
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