What is the perpendicular distance from the point (1, 2) to the straight line 3x + 4y - 1 = 0?
Answer and explanation
Correct answer: D. 2
- Step 1: Distance d = |a x0 + b y0 + c| / sqrt(a^2 + b^2). Step 2. d = |3(1) + 4(2) - 1| / sqrt(3^2 + 4^2) = |3 + 8 - 1| / 5 = 10 / 5 = 2. Answer: 2. Why not the others: 10 is the numerator before dividing by 5; 1 forgets the 8 in the numerator; 5 is the denominator.
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