What is the general solution of the equation cos(theta) = 0?
Answer and explanation
Correct answer: C. theta = (2n + 1) pi / 2
- Step 1: Cosine is zero at odd integer multiples of pi/2: pi/2, 3pi/2, -pi/2, etc. Step 2. The general solution is theta = (2n + 1) pi / 2 for integer n. Answer: theta = (2n + 1) pi / 2. Why not the others: n pi is where sin(theta) = 0; 2n pi is where cos(theta) = 1; n pi / 4 is not all roots.
Practise more Algebra, Conic Sections, Trigonometry and Mechanics.
Free questions with an explanation for every one, and full timed Higher Secondary Certificate Examination (Bangladesh) mock tests.
More Algebra, Conic Sections, Trigonometry and Mechanics questions
- If omega is an imaginary cube root of unity, what is the value of 1 + omega + omega^2?
- What is the value of omega^3 if omega is a cube root of unity?
- What is the modulus of the complex number z = 3 - 4i?
- What is the argument (in radians) of the complex number z = 1 + i?
- If alpha and beta are the roots of ax^2 + bx + c = 0, what is the product of roots alpha * beta?
- What is the discriminant of the quadratic equation 2x^2 - 5x + 3 = 0?