What is the bond order of a diatomic Oxygen molecule (O2) according to Molecular Orbital Theory?
Answer and explanation
Correct answer: D. 2
- Step 1: In O2 (16 electrons), there are 10 bonding electrons and 6 antibonding electrons: N_b = 10, N_a = 6. Step 2. Bond order = (N_b - N_a) / 2 = (10 - 6) / 2 = 4 / 2 = 2. Answer: 2. Why not the others: 1 is the bond order of F2 or H2; 3 is the bond order of N2; 1.5 is the bond order of superoxide ion O2-.
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