What is the bond order of a diatomic Nitrogen molecule (N2)?
Answer and explanation
Correct answer: A. 3
- Step 1: Nitrogen (14 electrons) has MO configuration with N_b = 10 bonding electrons and N_a = 4 antibonding electrons. Step 2. Bond order = (10 - 4) / 2 = 6 / 2 = 3 (one sigma and two pi bonds). Answer: 3. Why not the others: 2 is the bond order of diatomic Oxygen (O2); 1 is the bond order of Fluorine (F2); 2.5 is the bond order of Nitrogen monoxide (NO) or N2+ cation.
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