According to the Arrhenius equation k = A e^(-E_a / RT), what does plotting ln(k) against 1/T yield? (Hard)
Answer and explanation
Correct answer: D. A straight line with slope equal to -E_a / R
- Step 1: Taking the natural logarithm of both sides gives ln(k) = ln(A) - (E_a / R)(1/T). Step 2. This has the form y = c + m x with x = 1/T and slope m = -E_a / R. Answer: A straight line with slope equal to -E_a / R. Why not the others: Positive slope violates activation barrier thermodynamics; it is linear not parabolic; horizontal line implies zero activation energy.
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