According to the Nernst Equation, how is the electrode reduction potential affected as the concentration of reducible metal ions is raised?
Answer and explanation
Correct answer: D. Increases
- Step 1: Nernst equation for reduction M^(n+) + n e- -> M: E = E^\circ - (RT / nF) ln(1 / [M^(n+)]) = E^\circ + (0.0591 / n) log[M^(n+)]. Step 2. As [M^(n+)] increases, log[M^(n+)] increases, so electrode reduction potential E increases. Answer: Increases. Why not the others: Decreases reverses the logarithmic term; remains unchanged ignores concentration dependence; zero occurs only at specific equilibrium potential.
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