What is the hybrid state and shape of the Sulfate ion (SO4 2-)?
Answer and explanation
Correct answer: A. sp^3 hybridization, regular tetrahedral geometry
- Step 1: Sulfur in SO4 2- forms 4 equivalent sigma bonds with oxygen atoms with zero lone pairs (steric number 4). Step 2. The four bond pairs repel equally, producing sp^3 hybridization with a regular tetrahedral geometry (109.5 degree angles). Answer: sp^3 hybridization, regular tetrahedral geometry. Why not the others: sp^2 is trigonal planar; sp^3d^2 is octahedral (SF6); dsp^2 is square planar.
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