What type of hybridization is exhibited by the central Boron atom in Boric acid (H3BO3 or B(OH)3)?
Answer and explanation
Correct answer: C. sp^2 hybridization
- Step 1: In orthoboric acid B(OH)3, boron forms three single covalent bonds with OH groups and possesses no lone pairs. Step 2. Steric number is 3, corresponding to sp^2 hybridization with planar BO3 units linked by hydrogen bonds. Answer: sp^2 hybridization. Why not the others: sp^3 is found in the borate anion [B(OH)4]-; sp is linear; sp^3d is steric number 5.
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