A 0.10 kg ball dropped from a height of 5.0 m rebounds to a height of 3.2 m after hitting a concrete floor. How much mechanical energy was lost during the collision? (g = 9.8 m/s^2)

Answer and explanation

Correct answer: C. 1.76 J

  1. Step 1: Initial potential energy: PE_i = m g h_i = 0.10 9.8 5.0 = 4.90 J.
  2. Step 2: Final potential energy at peak rebound: PE_f = m g h_f = 0.10 9.8 3.2 = 3.136 J.
  3. Step 3: Energy dissipated as sound and heat: Delta E = PE_i - PE_f = 4.90 - 3.136 = 1.764 J approx 1.76 J.
Answer
1.76 J.
Why not the others: '4.90 J' is total initial energy; '3.14 J' is the remaining rebound energy; '0.88 J' divides energy loss by 2.

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