What happens to the internal energy of an ideal gas during an isothermal expansion?

Answer and explanation

Correct answer: A. It remains constant

  1. Step 1: For an ideal gas, internal energy U depends solely on absolute temperature T: U = (3/2) n R * T.
  2. Step 2: In an isothermal process, Delta T = 0, so Delta U = 0.
  3. Step 3: Heat absorbed by the gas is converted completely into work done: Q = W.
  4. Step 4: Thus internal energy remains constant.
Answer
It remains constant.
Why not the others: 'It increases because volume expands' ignores that intermolecular potential energy is zero in ideal gases; 'It decreases because work is done' overlooks that heat input balances work; 'It drops to zero' confuses delta with absolute zero.

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