What is the total area enclosed between the curves and ?

Answer and explanation

Correct answer: B.

  1. Step 1: Find intersections: and . On , . Area A = \int_0^1 (x - x^2) \, dx = \left[ \frac{x^2}{2} - \frac{x^3}{3} ight]_0^1 = \frac{1}{2} - \frac{1}{3} = \frac{1}{6}. **Answer: . Why not the others:** " unhalved area" evaluates only without subtracting from the line area; " triangle area" evaluates the triangular area without subtracting the parabolic region; " unit square" confuses the area of the bounding unit square with the enclosed curved segment.

Practise more Advanced Integration and Integral Equations.

Free questions with an explanation for every one, and full timed Panhellenic Examinations (Greece) mock tests.