What is the volume occupied by 2.50 moles of an ideal gas at Standard Temperature and Pressure (STP: 0°C and 1.00 atm)? (Molar volume at STP = 22.4 L/mol)

Answer and explanation

Correct answer: A. 56.0 L

  1. Step 1: At STP, one mole of any ideal gas occupies a standard molar volume of 22.4 liters.
  2. Step 2: Calculate total volume: V = n * V_m.
  3. Step 3: Substitute values: V = 2.50 mol * 22.4 L/mol = 56.0 L.
Answer
56.0 L.
Why not the others: '22.4 L' is the volume of 1.0 mole; '8.96 L' divides 22.4 by 2.50; '11.2 L' is the volume of 0.50 moles.

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