A simple pendulum has a length of 0.98 m on Earth, where g = 9.8 m/s^2. What is its approximate period of oscillation?

Answer and explanation

Correct answer: B. 2.0 s

  1. Step 1: Use the simple pendulum period formula: T = 2 pi sqrt(L / g).
  2. Step 2: Calculate ratio: L / g = 0.98 / 9.8 = 0.1.
  3. Step 3: Take square root: sqrt(0.1) is approximately 0.3162.
  4. Step 4: Multiply by 2 pi (approximately 6.283): T = 6.283 0.3162 = 1.99 s, which rounds to 2.0 s.
Answer
2.0 s.
Why not the others: '1.0 s' calculates the half-period; '3.14 s' multiplies by pi instead of 2*pi; '6.28 s' forgets to multiply by sqrt(L/g).

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