In a population in Hardy-Weinberg equilibrium, the frequency of an autosomal recessive allele (q) is 0.2. What is the expected frequency of heterozygous carriers (2pq) in this population?
Answer and explanation
Correct answer: A. 0.32 (32%)
Under Hardy-Weinberg equilibrium, p + q = 1. Given q = 0.2, the dominant allele frequency is p = 1 - 0.2 = 0.8. The frequency of heterozygous carriers is given by 2pq = 2 (0.8) (0.2) = 0.32 (or 32%). Homozygous dominant individuals represent p^2 = 0.64 (64%), and homozygous recessive individuals represent q^2 = 0.04 (4%).
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