A spring with a force constant k = 200 N/m is compressed by 0.10 m from its equilibrium length. How much elastic potential energy is stored in the compressed spring?
Answer and explanation
Correct answer: C. 1.0 J
The elastic potential energy stored in an ideal Hookean spring is given by U_s = (1/2) k x^2. Substituting the values: U_s = (1/2) (200 N/m) (0.10 m)^2 = 100 * 0.010 = 1.0 J.
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