What are the coordinates of the vertex of the parabola defined by the quadratic function f(x) = 2x^2 - 8x + 3?
Answer and explanation
Correct answer: C. (2, -5)
For a quadratic function f(x) = ax^2 + bx + c, the x-coordinate of the vertex is x_v = -b / (2a) = -(-8) / (2 * 2) = 8 / 4 = 2. The y-coordinate is f(2) = 2(2)^2 - 8(2) + 3 = 2(4) - 16 + 3 = 8 - 16 + 3 = -5. The vertex is at (2, -5).
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