In how many distinct ways can a committee of 3 members be selected from a group of 8 candidate doctors?
Answer and explanation
Correct answer: C. 56
The selection order does not matter, so we use combinations: C(n, k) = n! / [k! (n - k)!]. C(8, 3) = (8 7 6) / (3 2 * 1) = 336 / 6 = 56.
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