A compound light microscope has an objective lens with a focal length of 4.0 mm and an eyepiece with a focal length of 25 mm. If the tube length between the focal points is 160 mm and the near point of the human eye is 250 mm, what is the total magnification of the microscope?
Answer and explanation
Correct answer: B. 400x
The linear magnification of the objective is m_obj ≈ L / f_obj = 160 mm / 4.0 mm = 40x. The angular magnification of the eyepiece is m_eye = D / f_eye = 250 mm / 25 mm = 10x. Total magnification is the product of both lenses: M_total = m_obj m_eye = 40 10 = 400x.
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