A municipal water treatment facility recorded daily filtration volumes during a maintenance week: Monday = 45 megalitres (ML), Tuesday = 52 ML, Thursday = 68 ML, Friday = 75 ML, and an unmetered Wednesday. If the total filtration across all five days reached 300 ML, what was the mean daily volume over the five-day workweek?
Answer and explanation
Correct answer: C. 60 ML
- Step 1: Divide the given five-day total volume by the number of days: 300 ML / 5 days = 60 ML per day. Step 2. Wednesday volume is 300 - (45 + 52 + 68 + 75) = 300 - 240 = 60 ML, which matches the mean. Answer: 60 ML. Why not the others: 55 ML, 58 ML, and 62 ML result from computational slips.
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