What is the period of the trigonometric function f(x) = 4 * sin(3x - pi/2)?
Answer and explanation
Correct answer: B. 2*pi / 3
- Step 1: The period T of a sine function of the form y = A sin(Bx - C) is given by T = 2*pi / |B|.
- Step 2: Here B = 3, so the period is T = 2*pi / 3.
Answer
2*pi / 3.
Why not the others: '2pi' is the period of standard sin(x); 'pi / 3' is half the true period; '3pi / 2' inverts the frequency factor.
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