A magnetic flux through a 50-turn coil changes uniformly from 0.10 Wb to 0.30 Wb in 0.20 seconds. What is the magnitude of the induced EMF?

Answer and explanation

Correct answer: C. 50 Volts

  1. Step 1: Apply Faraday's Law of induction: |emf| = N * |Delta Phi / Delta t|.
  2. Step 2: |emf| = 50 |(0.30 - 0.10) / 0.20| = 50 (0.20 / 0.20) = 50 * 1.0 = 50 V.
Answer
50 Volts.
Why not the others: '10 Volts' forgets to multiply by the number of turns N = 50; '100 Volts' doubles the flux change; '25 Volts' divides by 2.

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