What is the de Broglie wavelength of an electron moving with momentum p = 3.315 10^-24 kgm/s? (h = 6.63 10^-34 Js)

Answer and explanation

Correct answer: A. 2.0 * 10^-10 meters

  1. Step 1: The de Broglie wavelength is given by lambda = h / p.
  2. Step 2: lambda = (6.63 10^-34 Js) / (3.315 10^-24 kgm/s) = 2.0 * 10^-10 m (0.20 nm).
Answer
2.0 * 10^-10 meters.
Why not the others: '5.0 10^-10 meters' inverts the quotient; '2.0 10^-9 meters' has an order of magnitude error; '1.0 * 10^-10 meters' divides by 2.

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