An electric kettle rated at 2,000 W operates for 180 seconds. How much electrical energy does it consume?
Answer and explanation
Correct answer: C. 360,000 Joules
- Step 1: Energy consumed is given by E = P * t.
- Step 2: E = 2,000 W * 180 s = 360,000 J (360 kJ).
Answer
360,000 Joules.
Why not the others: '11.1 Joules' divides power by time (2000/180); '18,000 Joules' drops a zero in multiplication; '60,000 Joules' computes 2000 * 30.
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