Find the 15th term of an arithmetic progression whose first term is 4 and common difference is 3.
Answer and explanation
Correct answer: A. 46
- Step 1: Recall the formula for the nth term of an AP: a_n = a_1 + (n - 1)d.
- Step 2: Substitute values: a_1 = 4, n = 15, d = 3: a_15 = 4 + (15 - 1)3 = 4 + 143 = 4 + 42 = 46.
Answer
46.
Why not the others: Option 49 uses n instead of (n - 1), calculating 4 + 15*3 = 49. Option 43 uses n - 2 = 13. Option 45 is an arithmetic addition slip (42 + 3 instead of 42 + 4).
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