In how many distinct ways can a committee of 3 students be chosen from a group of 8 eligible candidates?

Answer and explanation

Correct answer: D. 56

  1. Step 1: Use combinations since selection order does not matter: C(n, r) = n! / [r!(n - r)!].
  2. Step 2: Calculate C(8, 3): (8 7 6) / (3 2 1) = 336 / 6 = 56.
Answer
56.
Why not the others: Option 336 computes permutations P(8, 3) = 876, which assumes order matters. Option 24 calculates 8 * 3. Option 112 doubles the correct combination count.

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