In complex analysis, what is the geometric locus represented by ?

Answer and explanation

Correct answer: D. Perpendicular bisector of segment joining and

  1. Step 1: Equality represents equidistant points from and . Step 2. The locus of points equidistant from two fixed points in a plane is the perpendicular bisector of the segment connecting them. **Answer: Perpendicular bisector of segment joining and . Why not the others:** Circles require constant distance to one center; parabolas require focus-directrix distance.

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