What is the pH of an aqueous 0.010 M sodium hydroxide (NaOH) solution at 25 degrees Celsius (where Kw = 1.0 x 10^-14)?
Answer and explanation
Correct answer: A. pH = 12.0
NaOH dissociates completely: [OH-] = 0.010 M = 1.0 x 10^-2 M. pOH = -log[OH-] = 2.0. At 25 degrees C, pH + pOH = 14.0, so pH = 14.0 - 2.0 = 12.0.
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