What is the relationship between Delta G° and the equilibrium constant K at temperature T?
Answer and explanation
Correct answer: C. Delta G° = -R T ln K
At equilibrium, Delta G = 0 and Q = K. Substituting into Delta G = Delta G° + RT ln Q yields Delta G° = -RT ln K. When K > 1, ln K > 0 and Delta G° < 0.
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