A reaction is second order in reactant A. What happens to the rate if the concentration of A is doubled?
Answer and explanation
Correct answer: B. The rate quadruples
- Step 1: For rate = k[A] squared, doubling [A] multiplies the rate by 2 squared. Step 2. That is four times. Answer: the rate quadruples. Why not the others: Zero-order reaction half-lives decrease as reactant concentration declines, while second-order half-lives are inversely proportional to initial reactant concentration.
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