In chemical kinetics, when plotting ln k versus 1/T according to the Arrhenius relationship, what is the slope of the resulting straight line?
Answer and explanation
Correct answer: B. -Ea / R
- Step 1: Taking the natural logarithm of both sides of the Arrhenius equation: .
- Step 2: Rearranging into the standard linear equation form (): .
- Step 3: In a plot where and , the slope () is equal to , and the y-intercept () is .
- Step 4: (If plotted using vs , the slope would be ).
Answer
-Ea / R
Why not the others: '-Ea / (2.303 R)' is the slope when plotting common logarithm versus , not ; '+Ea / R' has the wrong positive sign; 'ln A' is the y-intercept, not the slope.
Practise more Chemical Kinetics.
Free questions with an explanation for every one, and full timed NEET UG mock tests.
More Chemical Kinetics questions
- For the gas-phase chemical reaction: N2(g) + 3 H2(g) -> 2 NH3(g), how is the rate of formation of ammonia (d[NH3]/dt) stoichiometrically rel…
- What are the dimensional units of the rate constant (k) for a chemical reaction of overall order n = 0 (zero-order reaction)?
- How does the half-life (t1/2) of a zero-order reaction depend on the initial concentration of the reactant ([A]0)?
- A first-order chemical reaction has a rate constant k = 6.93 * 10^-3 s^-1. What time is required for the reaction to reach 99.9 percent comp…
- Why is the acid-catalyzed hydrolysis of ethyl acetate (CH3COOC2H5 + H2O -> CH3COOH + C2H5OH) classified as a pseudo-first-order reaction?
- In the Arrhenius equation, k = A * e^(-Ea / RT), what does the slope of a linear plot of ln k versus 1/T represent?