25 cm of 0.5 mol/dm sodium hydroxide solution is neutralised by sulfuric acid of concentration 0.4 mol/dm according to 2NaOH + HSO → NaSO + 2HO. What volume of the acid is needed?

Answer and explanation

Correct answer: B. 62.5 cm

  1. Step 1: Moles of NaOH mol.
  2. Step 2: From the equation, 1 mol of acid reacts with 2 mol of NaOH, so moles of acid mol.
  3. Step 3: Volume of acid cm.
Answer
62.5 cm.
Why not the others: 15.6 cm: the mole ratio from the equation is applied the wrong way. 5 cm: it multiplies the concentrations and volume. 25 cm: it assumes equal volumes.

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25 cm 3 of 0.5 mol/dm 3 sodium hydroxide… | HKDSE (Hong Kong)