If sin x = 3/5 and x is in the second quadrant, what is cos x?
Answer and explanation
Correct answer: C. -4/5
- Step 1: sin^2 x + cos^2 x = 1, so cos^2 x = 1 - 9/25 = 16/25. Step 2. cos x = plus or minus 4/5, and in the second quadrant cosine is negative, so cos x = -4/5. Answer: -4/5. Why not the others: 4/5: In the second quadrant cosine is negative. -3/5: That is minus the sine, not the cosine. 5/4: That is the reciprocal.
Practise more Trigonometric functions.
Free questions with an explanation for every one, and full timed CSAT Suneung mock tests.
More Trigonometric functions questions
- What is the period of the function y = 3 sin (2x)?
- What is the maximum value of the function y = 5 cos x + 12 sin x?
- Find the value of sin 75 degrees x cos 15 degrees + cos 75 degrees x sin 15 degrees.
- Solve 2 sin x = 1 for x in the interval 0 to pi/2.
- What is the value of cos (2 pi/3)?
- In a triangle ABC, a = 7, b = 8 and C = 60 degrees. What is c^2?