A particle starts at rest with acceleration a(t) = 6t. What is its velocity at t = 2?
Answer and explanation
Correct answer: A. 12
- Step 1: v(t) = integral of 6t = 3t^2 + C, and v(0) = 0 so C = 0. Step 2. v(2) = 3 x 4 = 12. Answer: 12. Why not the others: 6: That is a(1). 24: That doubles the correct velocity. 36: That is a(6).
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