The velocity of a particle is v(t) = 3t^2 - 6t. What is its displacement from t = 0 to t = 2?
Answer and explanation
Correct answer: A. -4
- Step 1: Displacement = integral of (3t^2 - 6t) from 0 to 2 = [t^3 - 3t^2] from 0 to 2. Step 2. = (8 - 12) - 0 = -4. Answer: -4. Why not the others: 4: That has the wrong sign. 0: That is the velocity at t = 2. -12: That is not the integral.
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