In an acidic solution, 25 mL of 0.04 mol/L Fe is titrated with 0.02 mol/L KMnO (MnO + 5Fe + 8H → Mn + 5Fe + 4HO). What volume of KMnO is needed?
Answer and explanation
Correct answer: D. 10 mL
- Step 1: Moles of Fe mol.
- Step 2: MnO : Fe , so moles of MnO and volume mL.
Answer
10 mL.
Why not the others: 50 mL: the 1 : 5 mole ratio is ignored. 250 mL: the mole ratio is applied the wrong way. 25 mL: equal volumes are assumed.
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