Evaluate the integral of (2x^2+6x) dx from x = 0 to x = 3.
Answer and explanation
Correct answer: B. 45
- Step 1: Find the antiderivative: 2/3x^3+3x^2.
- Step 2: Evaluate it at 3 and subtract its value at 0 (which is 0).
- Step 3: Result: 45.
Answer
45.
Why not the others: '36' evaluates the integrand at the upper limit instead of integrating; '48' adds the upper limit to the antiderivative value; '108' integrates but forgets to divide by the new exponents 3 and 2.
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