A ball is kicked at 40 m/s at 45 degrees above level ground (g = 10 m/s^2, no air resistance). What is its horizontal range?
Answer and explanation
Correct answer: D. 160 m
- Step 1: The range is R = v^2 sin(2 theta) / g, and sin(90 degrees) = 1.
- Step 2: R = 40^2 x 1 / 10 = 160 m.
Answer
160 m.
Why not the others: '80 m' uses sin(45) instead of sin(90) = 1 in the range formula; '320 m' doubles the correct range; '4 m' divides the speed by g without squaring it.
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