A projectile is launched at 30 m/s at 30 degrees above the horizontal (g = 10 m/s^2). Find its maximum height.

Answer and explanation

Correct answer: D. 11.25 m

  1. Step 1: Maximum height H = v^2 sin^2(theta) / (2g).
  2. Step 2: sin^2(30) = 1/4, so H = 30^2 x (1/4) / 20 = 11.25 m.
Answer
11.25 m.
Why not the others: '45 m' omits sin^2(30) = 1/4 and uses v^2/(2g); '22.5 m' uses sin(30) = 1/2 without squaring it; '5.62 m' divides by 4g instead of 2g after squaring the sine.

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