What is the period of a simple pendulum of length 2.5 m? (take g = 10 m/s²)
Answer and explanation
Correct answer: C. π s
- Step 1: T = 2π√(L/g). Step 2. T = 2π√(2.5/10) = π s. Answer: π s. Why not the others: 0.2π s is what you get if you forget the factor 2π. 0.8π s is what you get if you forget the square root. 2π s is what you get if you use L in place of L/g.
Practise more Mechanics, Energy and Properties of Matter.
Free questions with an explanation for every one, and full timed ECAT Pakistan mock tests.
More Mechanics, Energy and Properties of Matter questions
- What force gives a mass of 18 kg an acceleration of 9 m/s²?
- What is the kinetic energy of a 20 kg body moving at 14 m/s?
- How much gravitational potential energy does a 3 kg mass gain when lifted 5 m? (take g = 10 m/s²)
- A force of 100 N acts at 60° to the horizontal and moves a body 6 m along the horizontal. How much work does it do?
- A machine does 1200 J of work in 10 s. What is its power?
- A force of 1000 N acts on an area of 2 m². What pressure does it exert?