In a population in Hardy–Weinberg equilibrium, the frequency of a recessive allele is 0.3. What proportion of the population are heterozygous carriers?
Answer and explanation
Correct answer: C. 0.42
- Step 1: With q = 0.3 and p = 0.7, the carriers number 2pq = 2 × 0.7 × 0.3 = 0.42. Answer: 0.42. Why not the others: 0.09, 0.21 and 0.49 don't fit.
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