In a population in Hardy-Weinberg equilibrium, the allele a has frequency 0.3. What is the frequency of heterozygotes Aa?
Answer and explanation
Correct answer: B. 0.42
- Step 1: With p = 0.7 and q = 0.3, the heterozygotes are 2pq = 2 x 0.7 x 0.3 = 0.42.
Answer
0.42.
Why not the others: 0.09 is q squared and 0.49 is p squared.
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