In an acidic solution, 10 mL of 0.04 mol/L Fe is titrated with 0.02 mol/L KMnO (MnO + 5Fe + 8H → Mn + 5Fe + 4HO). What volume of KMnO is needed?
Answer and explanation
Correct answer: B. 4 mL
- Step 1: Moles of Fe mol.
- Step 2: MnO : Fe , so moles of MnO and volume mL.
Answer
4 mL.
Why not the others: 20 mL: the 1 : 5 mole ratio is ignored. 100 mL: the mole ratio is applied the wrong way. 10 mL: equal volumes are assumed.
Practise more Oxidation and Reduction.
Free questions with an explanation for every one, and full timed General Education Diploma (GED Oman) mock tests.
More Oxidation and Reduction questions
- In an acidic solution, 10 mL of 0.02 mol/L Fe is titrated with 0.04 mol/L KMnO (MnO + 5Fe + 8H → Mn + 5Fe…
- In an acidic solution, 20 mL of 0.02 mol/L Fe is titrated with 0.04 mol/L KMnO (MnO + 5Fe + 8H → Mn + 5Fe…
- In an acidic solution, 25 mL of 0.04 mol/L Fe is titrated with 0.01 mol/L KMnO (MnO + 5Fe + 8H → Mn + 5Fe…
- In an acidic solution, 10 mL of 0.04 mol/L Fe is titrated with 0.01 mol/L KMnO (MnO + 5Fe + 8H → Mn + 5Fe…
- In the reaction Zn + Cu → Zn + Cu, which species is the reducing agent?