What pressure (in kPa) does 0.5 mol of an ideal gas exert in a 20 L container at 500 K? (R = 8.314 J/(mol K))
Answer and explanation
Correct answer: C. 103.9 kPa
- Step 1: Ideal gas law: p = n R T / V with V in cubic meters.
- Step 2: p = 0.5 x 8.314 x 500 / 0.02 = 103925 Pa = 103.9 kPa.
Answer
103.9 kPa.
Why not the others: The volume must be converted from liters to cubic meters; the other values are off by a power of ten.
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