A ray in air strikes a transparent material at 60 degrees to the normal and is refracted at 30 degrees. What is the refractive index of the material?
Answer and explanation
Correct answer: D. sqrt(3)
- Step 1: Snell's law: n1 sin(t1) = n2 sin(t2) with n1 = 1.
- Step 2: n2 = sin(60) / sin(30) = sqrt(3).
Answer
sqrt(3).
Why not the others: The index is the ratio sin(angle in air) / sin(angle in the material); the other values correspond to other angle pairs.
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