What pressure (in kPa) does 2 mol of an ideal gas exert in a 25 L container at 500 K? (R = 8.314 J/(mol K))
Answer and explanation
Correct answer: C. 332.6 kPa
- Step 1: Ideal gas law: p = n R T / V with V in cubic meters.
- Step 2: p = 2 x 8.314 x 500 / 0.025 = 332560 Pa = 332.6 kPa.
Answer
332.6 kPa.
Why not the others: The volume must be converted from liters to cubic meters; the other values are off by a power of ten.
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